Superslim
BF2s Frat Brother
+211|6662|Calgary
Can someone help?

252=5x+2y

How do you solve for x  and y?

Thanks
Eagle
Togs8896 is my evil alter ego
+567|6601|New Hampshire, USA
I'm a little rusty, but i think it goes:


For y:

252=5x+2y
/2        /2

126=5x+y
-5x      -5x

126-5x=y

For x:

252=5x+2y
-2y       -2y

252-2y=5x
/5         /5

(252-2y)/5=x
https://static.bf2s.com/files/user/14407/Sig_Pats.jpg
Andoura
Got loooollllll ?
+853|6609|Montreal, Qc, Canada
Y=

252 = 5x + 2y

252 - 5x = 2y

252/2 - 5x/2 = 2y/2

126 - 2.5x = y

Y = 126 - 2.5x

And same for X, no ????  and i can be wrong
Eagle
Togs8896 is my evil alter ego
+567|6601|New Hampshire, USA
Ah well I wasn't sure if he was going into decimals... damn math teachers can never make up their minds.  "You need exact answers"  "NO, leave it simplified"


GAH!
https://static.bf2s.com/files/user/14407/Sig_Pats.jpg
Andoura
Got loooollllll ?
+853|6609|Montreal, Qc, Canada

-=]NS[=-Eagle wrote:

Ah well I wasn't sure if he was going into decimals... damn math teachers can never make up their minds.  "You need exact answers"  "NO, leave it simplified"


GAH!
Actually i was looking at your answer, and now im not sure of mine looolll

I think we both suck in math , but who's wrong ?
Deadmonkiefart
Floccinaucinihilipilificator
+177|6676
y=-5/2x+126
x=-2/5y+252/5
Just remember: You can do anything to the problem as long as you remember to do it to the numbers on both sides of the equal sign ex: 1+1=2x is the same as 1+1+1=2x+1

Last edited by Deadmonkiefart (2007-05-15 21:15:49)

JetSniper
R.I.P [EPIC]Pfcguinn
+113|6307

Andoura wrote:

Y=

252 = 5x + 2y

252 - 5x = 2y

252/2 - 5x/2 = 2y/2

126 - 2.5x = y

Y = 126 - 2.5x

And same for X, no ????  and i can be wrong
yes same for x

i think this is a graph problem?
S.Lythberg
Mastermind
+429|6417|Chicago, IL
252=5x+2y

2y=252-5x

y=-5x/2+126

Linear graph, infinite answer possibilities.  crosses y axis @ y=126, slope of -5/2
Deadmonkiefart
Floccinaucinihilipilificator
+177|6676
Your welcome.
*Coughkarmacough ahemcough*
Yaocelotl
:D
+221|6620|Keyboard
When you have obtained the result of x and y, give in the equation of y a valor of 0 for x, do the calculation and you should get a result, with that result (of y of course) you chage the y to the result of the equation where you obtained y and it should give you the result of the equation for x.

It's been a while since I attended algebra class but still can remember some things every now and then .
Eminem344
Member
+1|6394|New Jersey
its not really that hard to do it u actually went through school but some of yall make it look hard
Yaocelotl
:D
+221|6620|Keyboard

-=]NS[=-Eagle wrote:

I'm a little rusty, but i think it goes:


For y:

252=5x+2y
/2        /2

126=5x+y
-5x      -5x

126-5x=y

For x:

252=5x+2y
-2y       -2y

252-2y=5x
/5         /5

(252-2y)/5=x
Look, for these equations you first choose the easier one, in this case y = 126 - 5x:

Assign any real value to x in equation y = 126 - 5x, and it should be like this: y = 126 - 5(1) (I gave the value of 1 to x)

You get y = 121

Substitute the value of y in equation 5x = 252 - 2y, and it should be like this: 5x = 252 - 2(121)

You get 5x = 10

And the you clear the 5 in x by dividing both sides of the equation like this: 5x/5 = 10/5

You get x = 2

So there, I made your homework .
power9787
Member
+10|6552
this easy wait until you get to multivariable calculus and differential equation, this is what u learn in college, but since i am special i get to learn it in my high school years
show you examples problem : integral( sec y tan x dx dy) and y'' + y = tan x  y''= second derivative of y


the solution to 252=5x+2y  (252-5x)/2=2y/2  (252-2y)/5=5x/5
x=(252-2y)/5 y=(252-5x)/2
are you in algebra 1 in middle or high school
this is hella easy even for freshman or 8th grader
power9787
Member
+10|6552
simplified version of answer is y=126-2.5x, x= 50.4-0.4y
Spazz
Member
+7|6536
i dont know

thats a valid answer
S.Lythberg
Mastermind
+429|6417|Chicago, IL

power9787 wrote:

this easy wait until you get to multivariable calculus and differential equation, this is what u learn in college, but since i am special i get to learn it in my high school years
show you examples problem : integral( sec y tan x dx dy) and y'' + y = tan x  y''= second derivative of y
Screw calculus........
Even if I did get a 5 on the AP test Junior year........
Wait until you use multiple integral equations to find the volume of non-linear solids.......
GodFather
Blademaster's bottom bitch
+387|6190|Phoenix, AZ
haffeys Chinese he can figure it out
Coolbeano
Level 13.5 BF2S Ninja Penguin Sensei
+378|6733

-=]NS[=-Eagle's got it.

First off, there is no single answer.

Generally for every variable you need an equation. 2 variables, 2 equations. Yes there are exceptions but not applicable in this case.

Read the question again, answer in what? In terms of Y and X? Then that's doable. But as for real numbers (can't be imaginary afaik) then there's an infinite possibilty of answers.

Last edited by Coolbeano (2007-05-15 23:41:34)

Vub
The Power of Two
+188|6465|Sydney, Australia
It's a straight liine. There are infinite sets of X and Y which satisfy that equation, not just one set.
~FuzZz~
.yag era uoy fi siht deaR
+422|6293|Orrstrayleea
There can be shitloads of answers, i did a test on algebra today
spuddy1981
Member
+10|6333|england
Looks like half a simultaneous equation.  You need one equation per variable, so for this you would need two equations.
Airwolf
Latter Alcoholic
+287|6690|Scotland
https://img501.imageshack.us/img501/3482/img013rw2.jpg

my life depended on that question lol, and I fucked it up.

Can anyone actually do it?
spuddy1981
Member
+10|6333|england
use x=(-b+-root(b^2 -4ac))/2a

give me a min

could have done it with out that equation.

x=1
y=4

both meet at that point

dont know if that proves its a tangent

Last edited by spuddy1981 (2007-05-16 03:09:27)

Tetrino
International OMGWTFBBQ
+200|6701|Uhh... erm...
Given some time, I think it's doable. Just move y to one side, differentiate the long equation and then use the completing the square method on the long one to find the coordinates. There's your explanation, but no actual numbers because I'm too darn lazy.
DrunkFace
Germans did 911
+427|6652|Disaster Free Zone

[E.F.L]Airwolf wrote:

http://img501.imageshack.us/img501/3482/img013rw2.jpg

my life depended on that question lol, and I fucked it up.

Can anyone actually do it?
y = 6 - 2x
xx + yy + 6x - 4y -  7 = 0

xx + (6 - 2x) (6 - 2x) + 6x - 4(6 -2x) - 7 = 0
xx + (36 - 12x - 12x + 4xx) + 6x - (24 - 8x) - 7 =0
5xx - 10x + 5 = 0
5(xx - 2x +1) = 0
(x - 1) (x - 1) = 0
x = 1
y = 6 - 2x so y = 4

Coordinance = (1,4)

As there is only 1 point of contact it must be a tangent. <--- woops this is wrong.

intergrate:
xx + yy + 6x - 4y - 7 = 0
2x + 2y dy/dx + 6 - 4 dy/dx = 0
(2y - 4) dy/dx = - (2x + 6)
dy/dx = - (2x + 6) / (2y - 4)

Sub (1,4) = -(2 + 6)/(8 - 4)
= -2
same gradient as y = 6 - 2x where both lines intersect making it the tangent.


Now anyone want help me? (actually I know the answer... can you figure it out?)

A friend of yours discovers an ancient parchment among
his late grandfathers papers given below. (Notice your “friend” did not give you
the islands location.)
Sail to − − − North latitude and − − − West longitude where
thou wilt find a deserted island. There lieth a large meadow, not
pent, on the north shore of the island where standeth a lonely
oak and lonely pine. There thou wilt also see an old gallows on
which we once were wont to hang traitors. Start thou from the
gallows and walk to the oak counting thy steps. At the oak thou
must turn right by an angle by a right angle and take the same
number of steps. Put here a spike in the groud. Now must thou
return to the gallows and walk to the pine counting thy steps. At
the pine thou must turn left by a right angle and see that thou
takest the same number of steps, and put another spike into the
ground. Dig halfway between the spikes; the treasure is there.
Your friend is seeking help because once arriving on the island there are no
gallows, they must have rotted away over the years.

a) Is it possible to find the treasure without the gallows?
b) If it is possible, where is the treasure? If it is not possible to find the treasure, explain why.

Last edited by DrunkFace (2007-05-16 03:28:52)

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