a = b
a² = ab
a² - b² = ab - b²
(a + b)(a - b) = b(a - b)
(a + b) = b
a + a = a
2a = a
2 = 1
???
a² = ab
a² - b² = ab - b²
(a + b)(a - b) = b(a - b)
(a + b) = b
a + a = a
2a = a
2 = 1
???
I think that's the part where it's impossible. If they are the same non-zero integer then one + the other they can not equal them selves.HaiBai wrote:
(a + b) = b
a + a = a
2a = a
2 = 1
???
That's what my geek friend is sayingFlaming_Maniac wrote:
I believe the problem is you can't divide by a variable if it makes the variable drop out of the equation.
not according to the OP, it says A=1 I believeKEN-JENNINGS wrote:
a=0
Last edited by Narupug (2009-07-02 22:03:41)
It is English.ATG wrote:
Post in English,
It's close enough to comprehend what I was saying.ATG wrote:
or as close as you can reasonably get.
Sure they do, but I could care less when it's the title.ATG wrote:
Spelling, grammar, punctuation, and capitalization count.
In the red step you are dividing by (a-b) which = 0. And as everyone knows you can't divide by zero....HaiBai wrote:
a = b
a² = ab
a² - b² = ab - b²
(a + b)(a - b) = b(a - b)
(a + b) = b
a + a = a
2a = a
2 = 1
???
DrunkFace wrote:
. And as everyone knows you can't divide by zero....
Last edited by -=]NS[=-Eagle (2009-07-03 00:59:36)
(a + b) = b if a + b = b then a = 0HaiBai wrote:
a = b
a² = ab
a² - b² = ab - b²
(a + b)(a - b) = b(a - b)
(a + b) = b
a + a = a
2a = a
2 = 1
???
Vub wrote:
If a = b, then (a-b)=0, and you can't divide both sides by (a-b) because you'd be dividing by zero.
a = bHaiBai wrote:
a = b
a² = ab
a² - b² = ab - b²
(a + b)(a - b) = b(a - b) | / (a - b)
(a + b) = b
a + a = a
2a = a
2 = 1
???
Last edited by Gawwad (2009-07-03 05:50:54)
He had a point though.ATG wrote:
AWM sent bizatch.