SteikeTa
Member
+153|7064|Norway/Norwegen/ Norge/Noruega
I just started a night course on the high school i went to some years ago. Took only first degree math. I'm taking second degree right now. Right now we are refreshing some of the first degree math. Damn there are so many things i don't remember. I am doing...... decent. Maybe not.
But this one i could not solve. So, can anyone solve this and tell/show me why the answer is what it is?

https://img1.putfile.com/thumb/9/26607465855.jpg

At first i thought that X was 1. When i put it to the test( left side compared to right side), and it was not correct.
Looked through what i had done and thought I had made one mistake and that X was 3/5...
Anyone can explain this one to me and show me how it is solved?

Thanks

Last edited by SteikeTa (2006-09-24 04:47:29)

luckeydogg
Member
+35|6845|C:/system32/pimp.exe
False...  No wait...  The answer is C: pickle
Swiss
Member
+20|6861
i got x = 5
Cybargs
Moderated
+2,285|7032
You fail at algebra...

answer is

5X-3 over 10
https://cache.www.gametracker.com/server_info/203.46.105.23:21300/b_350_20_692108_381007_FFFFFF_000000.png
Swiss
Member
+20|6861
this equation does have "= 0" right? It's not a minus sign is it?
naightknifar
Served and Out
+642|6877|Southampton, UK

6
_
50

Explanation - Calculator.
SteikeTa
Member
+153|7064|Norway/Norwegen/ Norge/Noruega

Swiss wrote:

this equation does have "= 0" right? It's not a minus sign is it?
Yes, its =0
Cybargs
Moderated
+2,285|7032

SteikeTa wrote:

Swiss wrote:

this equation does have "= 0" right? It's not a minus sign is it?
Yes, its =0
fuck... thought it was a minus sign.
https://cache.www.gametracker.com/server_info/203.46.105.23:21300/b_350_20_692108_381007_FFFFFF_000000.png
SteikeTa
Member
+153|7064|Norway/Norwegen/ Norge/Noruega

cyborg_ninja-117 wrote:

SteikeTa wrote:

Swiss wrote:

this equation does have "= 0" right? It's not a minus sign is it?
Yes, its =0
fuck... thought it was a minus sign.
hehe, good. cause i was like this: wtf??

Last edited by SteikeTa (2006-09-24 04:38:15)

Swiss
Member
+20|6861
Basically, if i remember, you cross multiply to get 10(4X-2) + 5(3X-1) = 0
                                                                        20X - 20 + 15X - 5  = 0
                                                                                        5X - 25   = 0
                                                                                               5X   = 25
                                                                                                   X = 5

Last edited by Swiss (2006-09-24 04:38:45)

Phatso
The Moisture
+49|7011|South Africa
x=1

er.. i mean x=5... damn algebra was a loooong time ago...

Last edited by Phatso (2006-09-24 04:40:24)

SteikeTa
Member
+153|7064|Norway/Norwegen/ Norge/Noruega

Swiss wrote:

Basically, if i remember, you cross multiply to get 10(4X-2) + 5(3X-1) = 0
                                                                        20X - 20 + 15X - 5  = 0
                                                                                        5X - 25   = 0
                                                                                               5X   = 25
                                                                                                   X = 5
But if you put it to the test, its wrong. Left side is not the same as right side. If you know what i mean
What i mean is that x has to be something that makes the left side to be zero. So it is the same as the right side.. witch is zero
On all the questions, after i have found x... i have to put it to the test afterwords

Last edited by SteikeTa (2006-09-24 04:43:07)

Reciprocity
Member
+721|6896|the dank(super) side of Oregon
my brain is stinging
jimmanycricket
EBC Member
+56|6971|Cambridge, England
((4x-2)/5)-((3x-1)/10) =0


<=> ((4x-2)/5) = ((3x-1)/10)

<=> 8x-4=3x-1

<=>5x=3

<=>x=3/5


TEST

((4(3/5)-2)/5)-((3(3/5)-1)/10) =0


<=> ((12/5 - 2)/5)-(9/5-1)/10) =0

<=> ((2/5)/5)-(4/5)/10) =0

<=> 0.08- 0.08 = 0


Edit. added TEST

Last edited by jimmanycricket (2006-09-24 04:51:24)

Reciprocity
Member
+721|6896|the dank(super) side of Oregon

jimmanycricket wrote:

((4x-2)/5)-((3x-1)/10) =0


=> ((4x-2)/5)=((3x-1)/10)

=> 8x-4=3x-1

=>5x=3

=>x=3/5
I also came up with that. but it's 5am and the batteries in my graphing calculator have been dead for 4 years.

([4x-2]/5)=([-3x+1]/10)
10(4x-2)=5(-3x+1)
40x-20=-15x=5
25x-15=0
(25x)/5=15/5
5x=3
x=3/5

Last edited by Reciprocity (2006-09-24 04:53:17)

ToiletTrooper
Member
+25|7091|WC
My answer = WTF!

Last edited by ToiletTrooper (2006-09-24 04:50:54)

SteikeTa
Member
+153|7064|Norway/Norwegen/ Norge/Noruega

jimmanycricket wrote:

((4x-2)/5)-((3x-1)/10) =0


=> ((4x-2)/5) = ((3x-1)/10)

=> 8x-4=3x-1

=>5x=3

=>x=3/5


TEST

((4(3/5)-2)/5)-((3(3/5)-1)/10) =0


((12/5 - 2)/5)-(9/5-1)/10) =0

((2/5)/5)-(4/5)/10) =0

0.08- 0.08 = 0


Edit. added TEST
Damn. I really dont understand what you did on the test when its written like that
Ow man this course is going to be hard...
Cybargs
Moderated
+2,285|7032
Just plug the X back in and see if you got the answer
https://cache.www.gametracker.com/server_info/203.46.105.23:21300/b_350_20_692108_381007_FFFFFF_000000.png
jimmanycricket
EBC Member
+56|6971|Cambridge, England
all i did was put x=3/5 into the equation and saw if i came to a logical truth

do i get karma for this or have i just wasted 5 minuets of my precious time?

Last edited by jimmanycricket (2006-09-24 04:54:11)

Reciprocity
Member
+721|6896|the dank(super) side of Oregon
distributive property
multiplication property
transitive property

a bunch of fucking properties
SteikeTa
Member
+153|7064|Norway/Norwegen/ Norge/Noruega

jimmanycricket wrote:

all i did was put x=3/5 into the equation and saw if i came to a logical truth
Yes i know
X is 3 over 5. 3/5. Meaning that i have to multiplie 3/5 to 4,  minus 2 and divide it with 5: the answer to that, minus: 3 multipli with 3/5... minus 1 divided with 10. Dont remember how to do this... so many fractures(dont know if fractures are the right words for it in english) probably not.
jimmanycricket
EBC Member
+56|6971|Cambridge, England
fractions...
clue. 2 = 10/5 's

you multiply fractions by multiplying the the top of the fraction eg. 5/5 times 5 = 25/5 =5 as expected as 5/5 =1

Last edited by jimmanycricket (2006-09-24 04:59:50)

Vub
The Power of Two
+188|6810|Sydney, Australia
Basic steps of algebra:

1. Put over common denominator, in this case, it is 10.

(8x - 4 - 3x + 1)/10 = 0

2. Simplify your numerator.

(5x - 3)/10 = 0

3. Now cross multiply, in this case you times 10 to both sides. 0 x any integer = 0

(5x - 3) = 0

4. Put unknowns on one side, put integers on the other side of the equation.

5x=3

5. Solve

Therefore x = 3/5
Reciprocity
Member
+721|6896|the dank(super) side of Oregon

SteikeTa wrote:

jimmanycricket wrote:

all i did was put x=3/5 into the equation and saw if i came to a logical truth
Yes i know
X is 3 over 5. 3/5. Meaning that i have to multiplie 3/5 to 4,  minus 2 and divide it with 5: the answer to that, minus: 3 multipli with 3/5... minus 1 divided with 10. Dont remember how to do this... so many fractures(dont know if fractures are the right words for it in english) probably not.
algebra is all about learing how to manipulate equations with math rules called "properties".  keep in mind, action => reaction.  you can do nearly anyting to an equation as long as you do it to both sides.

If x+2=0 then by subtracting 2 from both sides of the equation you get x=-2

Last edited by Reciprocity (2006-09-24 05:04:29)

Vub
The Power of Two
+188|6810|Sydney, Australia
Please note the above method is not the only method of solving this equation, so if you don't start like how I started, don't worry. Other steps you can take:

change equation to (4x - 2)/5 = (3x - 1)/10
then you cross multiply, collect like terms and so on so forth.

And if all else fails, trial and error is your best friend.

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