you guys are smrat
yep the answer is 3/5
1) multiply the whole damn equation by 10 to get this
2(4x-2)- (3x-1)=0--------- basically i c4 the denominator...lol
2) distributive property ( give ammo to every noob...lol)
2(4x-2)= 8x-4
-(3x-1)= -3x+1
3) simplify and snipe
8x-4-3x+1=0 goes into 5x=3
4) multiply 1/5 on each side ( like spawnkilling in the alley of karkland) of 5x=3 to get x=3/5
congratualtions, you have received a expert math badge.
exponential growth equation: Ae^x^2. for every good player out there, there are 2500 noobs out there waiting to spoil your fun
1) multiply the whole damn equation by 10 to get this
2(4x-2)- (3x-1)=0--------- basically i c4 the denominator...lol
2) distributive property ( give ammo to every noob...lol)
2(4x-2)= 8x-4
-(3x-1)= -3x+1
3) simplify and snipe
8x-4-3x+1=0 goes into 5x=3
4) multiply 1/5 on each side ( like spawnkilling in the alley of karkland) of 5x=3 to get x=3/5
congratualtions, you have received a expert math badge.
exponential growth equation: Ae^x^2. for every good player out there, there are 2500 noobs out there waiting to spoil your fun
wtf 4 pages of explaining?
did you found that one really hard?
we just had one paragraph where we were suppose to do 10 of those in 10 minutes lol
did you found that one really hard?
we just had one paragraph where we were suppose to do 10 of those in 10 minutes lol
Last edited by r00ts (2006-09-24 10:09:57)
Hehe.... i needed to know the testing of the equation. I have one more, witch i dont remember how to find the common nominator( ?) for. Dont know if that is the right word. What do i multiply with here??
Last one. Wont bother you guys after this one.
At first, i thought the answer was to multiply each side with x-2..... but after i did the testing on both sides, it was wrong. I think....
Last one. Wont bother you guys after this one.
At first, i thought the answer was to multiply each side with x-2..... but after i did the testing on both sides, it was wrong. I think....
Last edited by SteikeTa (2006-09-24 10:33:59)
wow just did this unit in pre calc. this dude it right. i got the same thing.jimmanycricket wrote:
((4x-2)/5)-((3x-1)/10) =0
<=> ((4x-2)/5) = ((3x-1)/10)
<=> 8x-4=3x-1
<=>5x=3
<=>x=3/5
TEST
((4(3/5)-2)/5)-((3(3/5)-1)/10) =0
<=> ((12/5 - 2)/5)-(9/5-1)/10) =0
<=> ((2/5)/5)-(4/5)/10) =0
<=> 0.08- 0.08 = 0
Edit. added TEST
(x+3)/(x-2) = (x+1)/(x)
Times both sides by (x-2)(X)
The (x-2) cancels on the left and the (X) cancels on the right to give.
=>(x+3)(x) = (x+1)(x-2)
=>X^2 + 3x = X^2 -2 -X
=>4X=-2
=>X=-0.5
TEST
(-0.5+3)/(-0.5-2) = (-0.5+1)/(-0.5)
=>(2.5)/(-2.5) = (0.5)/(-0.5)
=> -1 = -1
Times both sides by (x-2)(X)
The (x-2) cancels on the left and the (X) cancels on the right to give.
=>(x+3)(x) = (x+1)(x-2)
=>X^2 + 3x = X^2 -2 -X
=>4X=-2
=>X=-0.5
TEST
(-0.5+3)/(-0.5-2) = (-0.5+1)/(-0.5)
=>(2.5)/(-2.5) = (0.5)/(-0.5)
=> -1 = -1
Last edited by jimmanycricket (2006-09-24 10:46:36)
Code:
x^2 + 3x = (x-2)(x+1)
x^2 + 3x = x^2 - 1x - 2
4x + 2 = 0
4x = -2
x = -0.5Last edited by Nessie09 (2006-09-24 10:41:47)
Ah, so you multiply each side with the other side. That looks right... ill try it out now and see if i get the same.jimmanycricket wrote:
(x+3)(x) = (x+1)(x-2)
=>X^2 + 3x = X^2 -2 -X
=>4X=-2
=>X=-0.5
i think
Damn, thought i would get flamed like hell for these equations that you guys find easy
Trust me!!! Your help are really apreciated and NEEDED!!
to find the common denominator, you have to multiply each one by the other.SteikeTa wrote:
Hehe.... i needed to know the testing of the equation. I have one more, witch i dont remember how to find the common nominator( ?) for. Dont know if that is the right word. What do i multiply with here??
http://img1.putfile.com/thumb/9/26613293923.jpg
Last one. Wont bother you guys after this one.
At first, i thought the answer was to multiply each side with x-2..... but after i did the testing on both sides, it was wrong. I think....
so you have:
Code:
x(x+3)/x(x-2)=(X+2)(X+1)/x(x=2)
Last edited by Ender2309 (2006-09-24 10:43:09)
Hmm, i got x to be -1
Let me test that one on both sides now....
Let me test that one on both sides now....
Ok, sinds where doing maths:
(click to enlarge)
prove that ED is parallel to CF
been working on this all day, but can't figure it out
(click to enlarge)prove that ED is parallel to CF
been working on this all day, but can't figure it out
Ok, x cant be -1..... crap
(x+3)/(x-2) = (x+1)/(x) Times both sides by (X-2)
=> (x+3) = (x+1)(x-2)/(x) Times both sides by (X)
=>(x+3)(x) = (x+1)(x-2) Multiply out the brackets
=>X^2 + 3x = X^2 -2 -X Minus X^2 from both sides
=>3X=-2 -X Add X to both sides
=>4X=-2 Divide by 4
=>X=-0.5
added a step to make it easier
=> (x+3) = (x+1)(x-2)/(x) Times both sides by (X)
=>(x+3)(x) = (x+1)(x-2) Multiply out the brackets
=>X^2 + 3x = X^2 -2 -X Minus X^2 from both sides
=>3X=-2 -X Add X to both sides
=>4X=-2 Divide by 4
=>X=-0.5
added a step to make it easier
x(x-2) is the common denominator.
x(x+3) / x(x-2) = (x+1)(x-2) / x(x-2)
(x2 + 3x) = (x2 - x - 2) (I left out afew calc steps.. I hope you can follow)
4x = -2
x = -0.5
x(x+3) / x(x-2) = (x+1)(x-2) / x(x-2)
(x2 + 3x) = (x2 - x - 2) (I left out afew calc steps.. I hope you can follow)
4x = -2
x = -0.5
Sorry, I'm looking for nerd post is it here?
When i get to that step: =>X^2 + 3x = X^2 -2 -X.... i get on the right side: =x^2-2+xjimmanycricket wrote:
(x+3)/(x-2) = (x+1)/(x) Times both sides by (X-2)
=> (x+3) = (x+1)(x-2)/(x) Times both sides by (X)
=>(x+3)(x) = (x+1)(x-2) Multiply out the brackets
=>X^2 + 3x = X^2 -2 -X <---- why is the last x on the right side negativ? When i do it, its +x
=>3X=-2 -X Add X to both sides
=>4X=-2 Divide by 4
=>X=-0.5
added a step to make it easier
Last edited by SteikeTa (2006-09-24 11:14:21)
you do this:SteikeTa wrote:
jimmanycricket wrote:
(x+3)/(x-2) = (x+1)/(x) Times both sides by (X-2)
=> (x+3) = (x+1)(x-2)/(x) Times both sides by (X)
=>(x+3)(x) = (x+1)(x-2) Multiply out the brackets
=>X^2 + 3x = X^2 -2 -X <---- why is the last x on the right side negativ? When i do it, its +x
=>3X=-2 -X Add X to both sides
=>4X=-2 Divide by 4
=>X=-0.5
added a step to make it easier
(x+1)(x-2)
x*x = x^2 (as you prolly now)
x*1 = x
x*-2 = -2x
-2 * 1 = -2
x^2 + x - 2x - 2
combine
x^2 -x -2
throw the right over, multiply the left by 2. SOLVE
I'm sorry if you can't do year 7 maths...sergeriver wrote:
Sorry, I'm looking for nerd post is it here?
gah! maths, i got my GCSE let it haunt me no more...
give it to him, it was quite a funny post, well it made me laughDrunkFace wrote:
I'm sorry if you can't do year 7 maths...sergeriver wrote:
Sorry, I'm looking for nerd post is it here?
The answer is 42 or possibly G36 although I am leaning towards L96SteikeTa wrote:
I just started a night course on the high school i went to some years ago. Took only first degree math. I'm taking second degree right now. Right now we are refreshing some of the first degree math. Damn there are so many things i don't remember. I am doing...... decent. Maybe not.
But this one i could not solve. So, can anyone solve this and tell/show me why the answer is what it is?
http://img1.putfile.com/thumb/9/26607465855.jpg
At first i thought that X was 1. When i put it to the test( left side compared to right side), and it was not correct.
Looked through what i had done and thought I had made one mistake and that X was 3/5...
Anyone can explain this one to me and show me how it is solved?
Thanks
Last edited by syntaxmax642 (2006-09-24 11:33:36)
Ok, got it now and the test it self! Thanks all of you!!!
anyone?Nessie09 wrote:
Ok, sinds where doing maths:
prove that ED is parallel to CF
been working on this all day, but can't figure it out
nice to know we helped.SteikeTa wrote:
Ok, got it now and the test it self! Thanks all of you!!!
now wheres that karma.