I don't however understand how r can represent a 2D vector and be equal to the sum of two linear vectors in different directions. The only thing close I've seen to this representation is complex numbers z = x + iy, but even that, the vector is split into a modulus and argument part.bennisboy wrote:
correct, karmaramaVub wrote:
v = 2ti + 1.5(t^2)j
Last edited by Vub (2006-09-24 07:28:52)
Last edited by SteikeTa (2006-09-24 07:32:21)
Same as I...LaidBackNinja wrote:
Exactly. No calcutators needed. I just did it that way in 30 seconds.starkingdoms wrote:
just move the (3x - 1)/10 to the right side. multiply the left side by 2 to get rid of the fractions. then subtract 3x from the 8x, that gives 5x -2 = 1.
then add 2 to the right side, that gives 3. divide 3 by 5 giving x = 3/5
Have the same here.jimmanycricket wrote:
((4x-2)/5)-((3x-1)/10) =0
<=> ((4x-2)/5) = ((3x-1)/10)
<=> 8x-4=3x-1
<=>5x=3
<=>x=3/5
dont worry you'll get used to it n ffind it easy after a whileSteikeTa wrote:
Jesus.... some of you are young and still doing math like this? OR do you just have a very good memory? I now understand how to solve it So thanks!!!
BUT, i still dont understand how to solve the testing bit while using 3/5..... my brain is getting too old.
jimmanycricket gave me the first correct answer and showed the answer of the testing. But that way of writing it, Im just not used to it. Sorry, im a retard... What makes me crazy is the fact that this is the easiest of what im going to learn in this course!!!!!
Last edited by Sone (2006-09-24 07:49:47)
Its because r represents the position vector in a vertical plane. meaning that the overall position vector can be given by the horizontal and vertical components. Like how a co-ordinate on a graph is split into x and yVub wrote:
I don't however understand how r can represent a 2D vector and be equal to the sum of two linear vectors in different directions. The only thing close I've seen to this representation is complex numbers z = x + iy, but even that, the vector is split into a modulus and argument part.bennisboy wrote:
correct, karmaramaVub wrote:
v = 2ti + 1.5(t^2)j
But thanks for the karma
I get what you mean r constitutes both the horizontal and vertical components. But X and Y are separate. Adding two vectors in different directions is impossible. Unless we're not talking conventional vector addition.bennisboy wrote:
Its because r represents the position vector in a vertical plane. meaning that the overall position vector can be given by the horizontal and vertical components. Like how a co-ordinate on a graph is split into x and yVub wrote:
I don't however understand how r can represent a 2D vector and be equal to the sum of two linear vectors in different directions. The only thing close I've seen to this representation is complex numbers z = x + iy, but even that, the vector is split into a modulus and argument part.bennisboy wrote:
correct, karmarama
But thanks for the karma
Last edited by Vub (2006-09-24 08:08:59)
man I need a diagram. Its very basic vectors actually. say you have a triangle abc. with the distance ab given vector a and the distance bc given vector b. to find out the vector a to c, you just add b to a as it means you are getting from a to c. this gives a+b. it is just an expansion of that principle but from the origin.Vub wrote:
I get what you mean r constitutes both the horizontal and vertical components. But X and Y are separate. Adding two vectors in different directions is impossible. Unless we're not talking conventional vector addition.bennisboy wrote:
Its because r represents the position vector in a vertical plane. meaning that the overall position vector can be given by the horizontal and vertical components. Like how a co-ordinate on a graph is split into x and yVub wrote:
I don't however understand how r can represent a 2D vector and be equal to the sum of two linear vectors in different directions. The only thing close I've seen to this representation is complex numbers z = x + iy, but even that, the vector is split into a modulus and argument part.
But thanks for the karma
Edit: Different directions other than 180 deg
actually its basic GCSE vectors for the example I just gave. it will work out as the vector AC, If I had a diagram I'd prove it but I cant be bothered to make one.Vub wrote:
A vector consists of a magnitude and a direction. You will get neither one of them by adding the X and Y vectors.
In fact, using your example, adding a and b will give you a vector that's length ab+bc in either ab or bc's direction.
No adding 2 vectors will give you a third vector of different size and direction. His example with the triangle explains it the best.Vub wrote:
A vector consists of a magnitude and a direction. You will get neither one of them by adding the X and Y vectors.
In fact, using your example, adding a and b will give you a vector that's length ab+bc in either ab or bc's direction.
Last edited by DrunkFace (2006-09-24 08:31:42)
woo i got proved ritght without having to make a diagram cheers broDrunkFace wrote:
No adding 2 vectors will give you a third vector of different size and direction. His example with the triangle explains it the best.Vub wrote:
A vector consists of a magnitude and a direction. You will get neither one of them by adding the X and Y vectors.
In fact, using your example, adding a and b will give you a vector that's length ab+bc in either ab or bc's direction.
If you have 2 engines pushing you in differnt directions (vectors).
1. 10m/s north
2. 10m/s east
and you add them, you get sqrt 200 m/s North East your new vector.
Just complete the triangle and that third line is your new vector with a new size and direction.
EDIT: just found a diagram (has nothing to do with my example tho)
http://www.physics.uoguelph.ca/tutorial … 25anew.gif
By adding vectors A, B and C you get D.
You don't get 20m/s NE though, you get 10x(squareroot of 2) m/s NE.DrunkFace wrote:
No adding 2 vectors will give you a third vector of different size and direction. His example with the triangle explains it the best.Vub wrote:
A vector consists of a magnitude and a direction. You will get neither one of them by adding the X and Y vectors.
In fact, using your example, adding a and b will give you a vector that's length ab+bc in either ab or bc's direction.
If you have 2 engines pushing you in differnt directions (vectors).
1. 10m/s north
2. 10m/s east
and you add them, you get sqrt 200 m/s North East your new vector.
Just complete the triangle and that third line is your new vector with a new size and direction.
EDIT: just found a diagram (has nothing to do with my example tho)
http://www.physics.uoguelph.ca/tutorial … 25anew.gif
By adding vectors A, B and C you get D.
Can you please show me how?bennisboy wrote:
The first question I gave you can actually resolve the vectors to give one magnitude and one angle (if you designate a value for t).
You get squareroot (102 + 102) = squareroot of 200... which i put. Its a right angle triangle. You talked about imaginary numbers before yet your getting simple year 10 maths wrong, whats wrong with you.. getting old and forgetful?Vub wrote:
You don't get 20m/s NE though, you get 10x(squareroot of 2) m/s NE.DrunkFace wrote:
No adding 2 vectors will give you a third vector of different size and direction. His example with the triangle explains it the best.Vub wrote:
A vector consists of a magnitude and a direction. You will get neither one of them by adding the X and Y vectors.
In fact, using your example, adding a and b will give you a vector that's length ab+bc in either ab or bc's direction.
If you have 2 engines pushing you in differnt directions (vectors).
1. 10m/s north
2. 10m/s east
and you add them, you get sqrt 200 m/s North East your new vector.
Just complete the triangle and that third line is your new vector with a new size and direction.
EDIT: just found a diagram (has nothing to do with my example tho)
http://www.physics.uoguelph.ca/tutorial … 25anew.gif
By adding vectors A, B and C you get D.
Ok, next year, Ill probably understand what you guys are talking about. Since this course will probably cover this as well....bennisboy wrote:
basically see how he got root20 as his answer, if you have say 10i + 10j, draw a little triangle with 2 sides of 10, then use inverse tangent of 10/10, to get 45 deg, this gives us a vector of direction 45deg from horizontal and of magnitude root20. this will work for all vectors
lol, you'll understand the maths bit at least, hopefully. lol. where you from then?SteikeTa wrote:
Ok, next year, Ill probably understand what you guys are talking about. Since this course will probably cover this as well....bennisboy wrote:
basically see how he got root20 as his answer, if you have say 10i + 10j, draw a little triangle with 2 sides of 10, then use inverse tangent of 10/10, to get 45 deg, this gives us a vector of direction 45deg from horizontal and of magnitude root20. this will work for all vectors
Maybe not since you are writing in english
Im from Norway, Bodø. Far north. Have just enrolled in second degree math class. Night classes. Everyone is younger than me in that class..... hehe, but thats ok. I look young, so they dont knowbennisboy wrote:
lol, you'll understand the maths bit at least, hopefully. lol. where you from then?SteikeTa wrote:
Ok, next year, Ill probably understand what you guys are talking about. Since this course will probably cover this as well....bennisboy wrote:
basically see how he got root20 as his answer, if you have say 10i + 10j, draw a little triangle with 2 sides of 10, then use inverse tangent of 10/10, to get 45 deg, this gives us a vector of direction 45deg from horizontal and of magnitude root20. this will work for all vectors
Maybe not since you are writing in english
just coz you know that square root of -1 = I dosnt mean you know basic maths.DrunkFace wrote:
You get squareroot (102 + 102) = squareroot of 200... which i put. Its a right angle triangle. You talked about imaginary numbers before yet your getting simple year 10 maths wrong, whats wrong with you.. getting old and forgetful?Vub wrote:
You don't get 20m/s NE though, you get 10x(squareroot of 2) m/s NE.DrunkFace wrote:
No adding 2 vectors will give you a third vector of different size and direction. His example with the triangle explains it the best.
If you have 2 engines pushing you in differnt directions (vectors).
1. 10m/s north
2. 10m/s east
and you add them, you get sqrt 200 m/s North East your new vector.
Just complete the triangle and that third line is your new vector with a new size and direction.
EDIT: just found a diagram (has nothing to do with my example tho)
http://www.physics.uoguelph.ca/tutorial … 25anew.gif
By adding vectors A, B and C you get D.
Last edited by jimmanycricket (2006-09-24 10:00:14)
