BF2S Forums Another math tread. :)

I think you mean differentiation.

1.

Huh? No. You need to use the product rule. You get:

h'(x) = 2*exp(x) + 2*x*exp(x)

http://en.wikipedia.org/wiki/Product_rule

brb, giving a presentation on Atomic Clocks.

I think the first one is 2xe^x + 2e^x
since I think it's the same as D f(x)g(x) = f(x)g'(x) + g(x)f'(x) ??


Edit:

k(x) = 2x * (ln x)²
follows the same rule

2x * 2(lnx)^2-1 * (1/x) + 2 * (ln x)²





(1/x) This is the derivative of ln|x| (i.e. the inner function). Since (ln x)² is positive it works the same as ln|x|

Last edited by Gawwad (2009-03-12 08:31:20)

SteikeTa wrote:

Aaaaahhh, damn it!!! The product rule, of course! Jesus, I always fail to remember those rules! So many of them :S

My most useful piece of paper for all of high school maths.