I have the following question:
(-3a^5b^-3c^0)^-2
As I'm simplifying, I'm getting 1/9a^-10b^6, and then c^0 to the power of -2 would still remain c^0, meaing it equals 1, or just c, correct? Do I leave it in the equation or get rid of it? I know I still have negative exponents, I'll get rid of them after this.
So should it be 1/9a^-10b^6c^0
or should it be 1/9a^-10b^6 (with no c in the equation)
Thanks to anyone who helps.
(-3a^5b^-3c^0)^-2
As I'm simplifying, I'm getting 1/9a^-10b^6, and then c^0 to the power of -2 would still remain c^0, meaing it equals 1, or just c, correct? Do I leave it in the equation or get rid of it? I know I still have negative exponents, I'll get rid of them after this.
So should it be 1/9a^-10b^6c^0
or should it be 1/9a^-10b^6 (with no c in the equation)
Thanks to anyone who helps.