Flaming_Maniac
prince of insufficient light
+2,490|6954|67.222.138.85
A series must be decreasing and its limit must be zero for it to have a chance at converging - but this does not prove convergence. All you can do is prove that it is divergent if one of those conditions is not true.

Looks like you should use the root test on that one.

p.s. fuck sequences and series
Bevo
Nah
+718|6768|Austin, Texas

Flaming_Maniac wrote:

A series must be decreasing and its limit must be zero for it to have a chance at converging - but this does not prove convergence. All you can do is prove that it is divergent if one of those conditions is not true.

Looks like you should use the root test on that one.

p.s. fuck sequences and series
prof didnt quite get to root test today. hw due tomorrow in discussion

you dont have kim by any chance?

no idea how to compute this bitch...
Flaming_Maniac
prince of insufficient light
+2,490|6954|67.222.138.85
408D last sem

root test is take the limit as var -> infinity of the whole thing raised to the (1/n)

That is to say lim n -> infinity of [en / 3n-1]1/n

If it's less than one, it converges. If it's greater than one, it diverges. If it's equal to one, the test is inconclusive.

in this case you get e/3 which is just under 1
Bevo
Nah
+718|6768|Austin, Texas
doesnt that just mean it approaches 0 though?

i mean its obvious that e/3 is < 1 and raised to some power n is going to eventually make its way towards 0, I thought that was the point of a limit

what's the difference of raising it to 1/n? I dont really follow your calc... I mean you could just take 3n-1 and call it 3n for calculation's sake, take the n out of e/3 and cancel it with the 1/n. but then you're right back where you started with a limit no?

ed: forgot i'm supposed to find what it converges at.

Doing this partial sum thing... looks like I got

sum (n = 1 --> inf)  = e / (1 - e/3)

Is this correct? I'm just trying to follow this stupid book. My TA is completely useless and my prof never really explained partial sums that well.

Last edited by Bevo (2010-02-09 18:30:51)

Flaming_Maniac
prince of insufficient light
+2,490|6954|67.222.138.85
http://en.wikipedia.org/wiki/Root_test#Proof

haha what do you want from me

The key is the problem isn't just a limit, you have to see not just if the terms go to zero, but if the addition of the terms is some constant. The root test is one of the tests you use to prove that convergence.

pretty sure partial sums is of a finite number of terms? not n -> infinity
Bevo
Nah
+718|6768|Austin, Texas

Flaming_Maniac wrote:

http://en.wikipedia.org/wiki/Root_test#Proof

haha what do you want from me

The key is the problem isn't just a limit, you have to see not just if the terms go to zero, but if the addition of the terms is some constant. The root test is one of the tests you use to prove that convergence.

pretty sure partial sums is of a finite number of terms? not n -> infinity
dunno! like i said my TA is useless so i have no practice doing this, i just have a bit of what my prof scrobbled on the board

so it's convergent yeah, but how do you find the sum?

the book tells me

sn = a/(1 - r) for |r| < 1. r seems to be e/3 so we're all good there, and messing around with the exponents gives me e as the constant, I believe.

giving me s = e / (1 - (e/3)). Does this look correct to you?
Flaming_Maniac
prince of insufficient light
+2,490|6954|67.222.138.85
Bevo
Nah
+718|6768|Austin, Texas
yeah ive just figured out how to do it on wolfram, things are moving much smoother

the fuck if I can do this on an exam though shit
Jenspm
penis
+1,716|6979|St. Andrews / Oslo

'aight, relatively large test tomorrow.. I've got everything revised, but I still have vectors left. Halp.

#1

O=(0,0,0), A=(4,4,2), B=(3,1,3), C=(-1-3-1), D=(2,5,4)

Find the Area of OABCD


Correct Answer: 14
#2

l: x=4t and y=2-t and z=1+t
m: x=2+t and y=2t and z=4-t

What is the distance between the two lines?


Correct Answer: 1.45
#3

Plane: 4x+6y+3z=12

A sphere surface with the center at (0,0,0) has a point in common with the plane. Determine the equation for the sphere surface.


Correct Answer: x^2 + y^2 + z^2 = 144/61
Book is of no use.. Can someone explain this to me?


Merci <33

Last edited by Jenspm (2010-02-10 09:24:59)

https://static.bf2s.com/files/user/26774/flickricon.png https://twitter.com/phoenix/favicon.ico
Bevo
Nah
+718|6768|Austin, Texas
#1. Separate into triangles, find area of triangles (.5bh)

#2. Substitute t = 1 and then find the resultant vector using vector subtraction then pythag? Dunno, that looks funky. Can you take a picture and upload it?

#3. looks like 122/42 + 62 + 32, whatever that means to you. Should give you the answer = X2 / A2 + B2 + C2.

Last edited by Bevo (2010-02-10 10:30:26)

Bevo
Nah
+718|6768|Austin, Texas
fook

Frictionless horizontal surface

F(1) = 20N------------->[1kg block][8kg block][4kg block]<------------F(2)= 7N

What is the magnitude of force exerted on the 8kg block by the block with mass 4kg?


I have no fooking clue! They'd all be sliding to the right with a magnitude of 13N forever, wouldn't they? I've already answered "0", "7", and "13" and none of them are right. I suck at forces in motion.
mcminty
Moderating your content for the Australian Govt.
+879|6968|Sydney, Australia

Bevo wrote:

#1. Separate into triangles, find area of triangles (.5bh)
It's been over a year since I've done this at uni ( tbh, loved it), but aren't those vector coordinates in 3D space.. o.O And thus you can't really find the area...

unless those coordinates form a shape on a plane.. tho it's not obvious at first glance
Flaming_Maniac
prince of insufficient light
+2,490|6954|67.222.138.85

Bevo wrote:

fook

Frictionless horizontal surface

F(1) = 20N------------->[1kg block][8kg block][4kg block]<------------F(2)= 7N

What is the magnitude of force exerted on the 8kg block by the block with mass 4kg?


I have no fooking clue! They'd all be sliding to the right with a magnitude of 13N forever, wouldn't they? I've already answered "0", "7", and "13" and none of them are right. I suck at forces in motion.
Isn't it 27N?
Arc
silly one-liner
+24|6706|Ontario
Wouldn't it be 14N?

F=ma
So the a = 7/4 on the 4kg block
F = 8 * 7/4 = 14N
Bevo
Nah
+718|6768|Austin, Texas
Errr, Arc sounds right. What were you thinking FM?
Bevo
Nah
+718|6768|Austin, Texas
arc was not correct..

Incorrect answers are 0, 7, 6, 13, 14.
nukchebi0
Пушкин, наше всё
+387|6571|New Haven, CT
Do you know if the collision is elastic or inelastic?
nukchebi0
Пушкин, наше всё
+387|6571|New Haven, CT
If it is frictionless, then I'm assuming net force on the system is 13N in the positive direction. Net force =/= the internal force, though, and in this case, F(4->8) should be the direct force from 4 hitting 8 and the opposite force from 8 hitting 4. Unless my shaky knowledge of mechanics fails me, it should be 27N, as FM suggested.
Bevo
Nah
+718|6768|Austin, Texas

nukchebi0 wrote:

If it is frictionless, then I'm assuming net force on the system is 13N in the positive direction. Net force =/= the internal force, though, and in this case, F(4->8) should be the direct force from 4 hitting 8 and the opposite force from 8 hitting 4. Unless my shaky knowledge of mechanics fails me, it should be 27N, as FM suggested.
also incorrect

And elastic/inelastic was not given in the problem.

fail question tbh
nukchebi0
Пушкин, наше всё
+387|6571|New Haven, CT
Hmm, well it's 12:30 and I'm writing an English paper.

Why is it wrong, though? You should be able to assume what I said in the first sentence. Can you go from there?
Bevo
Nah
+718|6768|Austin, Texas

nukchebi0 wrote:

Hmm, well it's 12:30 and I'm writing an English paper.

Why is it wrong, though? You should be able to assume what I said in the first sentence. Can you go from there?
Definitely not as I have no bloody clue

Believe me I spent a long time trying to do this many different ways and none of my answers have been correct. It's just a terrible question.

I might be able to see the correct answer once it's submitted at 4am tomorrow.
nukchebi0
Пушкин, наше всё
+387|6571|New Haven, CT
How are you knowing certain answers are wrong if you can't know the right answer? Have you tried inputting 27 into the online problem set sheet I assume you are using?

Since I can't dedicate the time to helping you, I'll tell you to search hyperpysics in google and peruse the site. You might find something useful there.

Last edited by nukchebi0 (2010-02-15 21:55:21)

Bevo
Nah
+718|6768|Austin, Texas

nukchebi0 wrote:

How are you knowing certain answers are wrong if you can't know the right answer? Have you tried inputting 27 into the online problem set sheet I assume you are using?
yes, 27 along with the ones I listed earlier were used as "tries" to answer the problem. I only have one left.
nukchebi0
Пушкин, наше всё
+387|6571|New Haven, CT

Bevo wrote:

nukchebi0 wrote:

How are you knowing certain answers are wrong if you can't know the right answer? Have you tried inputting 27 into the online problem set sheet I assume you are using?
yes, 27 along with the ones I listed earlier were used as "tries" to answer the problem. I only have one left.
Oh, okay. Sorry I couldn't help more. Good luck.
WldctARCHe
Member
+9|5605|Kansas
Correct answer should be 4N... The acceleration of all the blocks as one unit equals 1 m/s . F=ma => a=F/m => a=13N/13kg.
Thus the force from the 4kg block is F=ma => F=(4kg)(1m/s) => F=4N.
Hope this is right and hope this helps!

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