If f (x) = 2x^2 +2x -1 find
a) f (0)
a) f (0)
I made a visual for you...Canadianloser wrote:
thats 100% correct! says so in the back of the book, i just need to know how to get that...care to explain??DoctorFruitloop wrote:
I may be wrong, but I get the larger square at 11.314 units along a side.
Last edited by Icleos (2006-10-15 11:24:41)
f (x) = 2(x)^2 + 2(x) - 1deadawakeing wrote:
If f (x) = 2x^2 +2x -1 find
a) f (0)
f (0) = 2(0)^2 + 2(0) - 1
f (0) = 0 + 0 - 1
f (0) = -1
Last edited by Icleos (2006-10-15 11:40:40)
anyone here do coursework on My Place in Geography?
Bloody took some time!
Bloody took some time!
i'm dutch. Is there someone who want to make my (test)paper english tomorow?
Last edited by xINTERMISSIONx (2006-10-15 11:44:02)
Am it too late i might have it.Nessie09 wrote:
No idea, but since we are doing homework: (yes this was in the math topic aswell)
http://img1.putfile.com/thumb/9/26613451733.jpg(click to enlarge)
prove that ED is parallel to CF
been working on this all day, but can't figure it out
Make a tangent on ED. Join CF, then use Z angles.
Dude he posted that nearly a month ago...=Karma-Kills= wrote:
Am it too late i might have it.Nessie09 wrote:
No idea, but since we are doing homework: (yes this was in the math topic aswell)
http://img1.putfile.com/thumb/9/26613451733.jpg(click to enlarge)
prove that ED is parallel to CF
been working on this all day, but can't figure it out
Make a tangent on ED. Join CF, then use Z angles.
I wouldn't specifically use my answers but this is what I know from experience...jord wrote:
1.What happens to muscle fibres when we exercise and train them regulary?
2.Why is it so important that we train specific muscles when doing sport?
3.Which muscle is being described and where would it be found
a]Used particulary in throwing events and gives stability to the shoulder joint.
b]Responsible for bending the arm and elbow.
c]Used for climbing or pulling a rope.
d]Rear of the upper leg.
e]major role in sit ups.
As you can tell this is P.E homework,if anyone can help you wouldn't know how greatful i would be.
The only reward i can offer is karma,and a big thank you.
1.What happens to muscle fibres when we exercise and train them regulary?
Regularly trained muscle fibers become more flexible and dense over a long period of time.
This increases our strength and physical range of motion.
2.Why is it so important that we train specific muscles when doing sport?
Helps increase our performance and reduces the chances of becoming injured.
3.Which muscle is being described and where would it be found
a]Used particulary in throwing events and gives stability to the shoulder joint.
b]Responsible for bending the arm and elbow.
c]Used for climbing or pulling a rope.
d]Rear of the upper leg.
e]major role in sit ups.
You can find them yourself...
Last edited by Icleos (2006-10-15 12:03:58)
using that line i guess u will get a F in your essayIt's for an Engish essay
Are you in grade 11 in Ontario?deadawakeing wrote:
If f (x) = 2x^2 +2x -1 find
a) f (0)
Because thats exactly what im doing in math right now
Thanks Iceos.
Maths!
"Taking f(x) = 1/4x^4 - 4x^2 +25, find the values for which f`(x)=0"
So, 1/4x^4 - 4x^2 +25 = 0
But how do you solve that?
(Reads, One quarter x to the 4 - four x squared + 25 if that helps)
Karma for answer...
"Taking f(x) = 1/4x^4 - 4x^2 +25, find the values for which f`(x)=0"
So, 1/4x^4 - 4x^2 +25 = 0
But how do you solve that?
(Reads, One quarter x to the 4 - four x squared + 25 if that helps)
Karma for answer...
hey dont get all "techie" with the english, most dumbasses wont know wtf you're on about, i believe cheating is the word.daffytag wrote:
why not post you homework for people to copy A bit of plagiarism never hurt anyone. Plus who would know?
edit: i knew i forgot something
what is the answer to;
42 / 24
Last edited by surgeon_bond (2006-10-16 11:52:53)
You've got to be kidding me.
16/16 = 1
16/16 = 1
Do you mean f(x)=0 or f`(x)=0 - The two are actually very different mathemtatically=Karma-Kills= wrote:
Maths!
"Taking f(x) = 1/4x^4 - 4x^2 +25, find the values for which f`(x)=0"
So, 1/4x^4 - 4x^2 +25 = 0
But how do you solve that?
(Reads, One quarter x to the 4 - four x squared + 25 if that helps)
Karma for answer...
If its simply f(x)=0 then simply equate the function to zero and re-arrange for x - you may need to factorise the equation as i suspect there will be numerous roots as its a 4th order polynomial
If it is actually f`(x)=0 then let me know as thats slightly more complex, cant be arsed to type that now
Good luck
Last edited by Mong0ose (2006-10-16 15:00:43)
... and you?Mr.H@x0r wrote:
using that line I guess you will get an F in your essayIt's for an Engish essay
Last edited by NiMhurchu (2006-10-16 15:26:25)
Well did a quick calculation on your problem (could maybe wrong)=Karma-Kills= wrote:
Maths!
"Taking f(x) = 1/4x^4 - 4x^2 +25, find the values for which f`(x)=0"
So, 1/4x^4 - 4x^2 +25 = 0
But how do you solve that?
(Reads, One quarter x to the 4 - four x squared + 25 if that helps)
Karma for answer...
solution includes complex numbers
Hope I could help you
Edited for correcting a calculation failure
Last edited by BobbyD. (2006-10-18 05:48:55)
My solution: 42
or dont do homework at all, and then get a 2200 on your SAT
or dont do homework at all, and then get a 2200 on your SAT
Thanks very much for the quick reply and the effort into the help given +1BobbyD. wrote:
Well did a quick calculation on your problem (could maybe wrong)=Karma-Kills= wrote:
Maths!
"Taking f(x) = 1/4x^4 - 4x^2 +25, find the values for which f`(x)=0"
So, 1/4x^4 - 4x^2 +25 = 0
But how do you solve that?
(Reads, One quarter x to the 4 - four x squared + 25 if that helps)
Karma for answer...
solution includes complex numbers
http://img45.imageshack.us/img45/7671/rechnungxq1.jpg
Hope I could help you
Its not right - I think it reads .25x^4 - 4x^2 + 25=Karma-Kills= wrote:
Thanks very much for the quick reply and the effort into the help given +1BobbyD. wrote:
Well did a quick calculation on your problem (could maybe wrong)=Karma-Kills= wrote:
Maths!
"Taking f(x) = 1/4x^4 - 4x^2 +25, find the values for which f`(x)=0"
So, 1/4x^4 - 4x^2 +25 = 0
But how do you solve that?
(Reads, One quarter x to the 4 - four x squared + 25 if that helps)
Karma for answer...
solution includes complex numbers
http://img45.imageshack.us/img45/7671/rechnungxq1.jpg
Hope I could help you
So you have a quadratic.
Last edited by Pug (2006-10-17 09:33:44)
Before anyone says that this is just random bullshit...no, it isn't.Sgt.Scream.MDK wrote:
...Implement a BCD to a 7-segment display using an 8:1 mux, showing the truth table and karnaugh maps for each output ... yeah, didn't think so.
Scream: It's been such a long time since I actively engaged in component-level electronics that I'd have to wrap my brain around that one for a bit, but it seems to me as if you already pretty much have it, and were just posting it here to look elite.
Boolean algebra 4 teh intimidation win, eh? Does your professor make you write down about over twenty pages of notes per class?
Last edited by unnamednewbie13 (2006-10-17 10:25:20)
Wtf Stop Cheating "noobs" And Do Your Own Homework
Well actually i got a different answer, but thanked him for his effort.Pug wrote:
Its not right - I think it reads .25x^4 - 4x^2 + 25=Karma-Kills= wrote:
Thanks very much for the quick reply and the effort into the help given +1BobbyD. wrote:
Well did a quick calculation on your problem (could maybe wrong)
solution includes complex numbers
http://img45.imageshack.us/img45/7671/rechnungxq1.jpg
Hope I could help you
So you have a quadratic.
Basically
f (x) = 1/4x^4 - 4x^2 +25 = 0
f`(x) = 4x^3 - 8x =0
Do the difference of 2 squares and get x = 0 or x = 2+- Square Root 2
Ahh missed the f prime...
isn't f prime
x^3 - 8x = 0 though?
1/4x^4 prime = 4 * 1/4 x^(4-1) = 1x^3
I can't really remember though...
isn't f prime
x^3 - 8x = 0 though?
1/4x^4 prime = 4 * 1/4 x^(4-1) = 1x^3
I can't really remember though...
Last edited by Pug (2006-10-17 11:26:36)
=Karma-Kills= wrote:
....
Well actually i got a different answer, but thanked him for his effort.
Basically
f (x) = 1/4x^4 - 4x^2 +25 = 0
f`(x) = 4x^3 - 8x =0
Do the difference of 2 squares and get x = 0 or x = 2+- Square Root 2
You both are right there was a little calculation failure in my solution (corrected now).Pug wrote:
Ahh missed the f prime...
isn't f prime
x^3 - 8x = 0 though?
1/4x^4 prime = 4 * 1/4 x^(4-1) = 1x^3
I can't really remember though...
Notice: Don't do math after 4 beer