baking soda + water + ...
wait a tick, i think the doc that my group-mate sent me already had the answers on it... thanks lolDesertFox- wrote:
Correct me if I'm wrong, but it is balanced, isn't it?Gooners wrote:
can someone good at chem help me balance this?
C18H32O16 + H2O => C12H22O11 + C6H12O6
make me more commercially aware? Job interview on Tuesday and I need to ass kiss.
heh I remember when I had my 1st real job interview I wore glasses, made me look older and more experienced..teddy..jimmy wrote:
make me more commercially aware? Job interview on Tuesday and I need to ass kiss.
Ha...not a bad idea. Napoleon Dynamite style glasses maye?.Sup wrote:
heh I remember when I had my 1st real job interview I wore glasses, made me look older and more experienced..teddy..jimmy wrote:
make me more commercially aware? Job interview on Tuesday and I need to ass kiss.
bloody interview is 4 hours...urghh
No I only had a frameless pair of glasses besides sunglasses so those were the ones I wore at that time. It did the trick..teddy..jimmy wrote:
Ha...not a bad idea. Napoleon Dynamite style glasses maye?.Sup wrote:
heh I remember when I had my 1st real job interview I wore glasses, made me look older and more experienced..teddy..jimmy wrote:
make me more commercially aware? Job interview on Tuesday and I need to ass kiss.
..teddy..jimmy wrote:
Ha...not a bad idea. Napoleon Dynamite style glasses maye?.Sup wrote:
heh I remember when I had my 1st real job interview I wore glasses, made me look older and more experienced..teddy..jimmy wrote:
make me more commercially aware? Job interview on Tuesday and I need to ass kiss.
libertarian benefit collector - anti-academic super-intellectual. http://mixlr.com/the-little-phrase/
and more sophisticated...great specs thereUzique wrote:
http://www.go-optic.com/DFRAMES/IMAGES/ … 4_2000.jpg..teddy..jimmy wrote:
Ha...not a bad idea. Napoleon Dynamite style glasses maye?.Sup wrote:
heh I remember when I had my 1st real job interview I wore glasses, made me look older and more experienced
Last edited by ..teddy..jimmy (2010-09-15 10:24:56)
I'll need something stronger than glasses to keep me attentive for 4 hours.
i have the squarer ones. go for them jimmy they'll suit your chiselled jaw and suave looks.
you have approx. 3 hrs to go get some. good luck.
your future career depends upon it.
you have approx. 3 hrs to go get some. good luck.
your future career depends upon it.
libertarian benefit collector - anti-academic super-intellectual. http://mixlr.com/the-little-phrase/
Career in city law? Show the employers you have testicles with a shnazzy pair of spectacles. waheyyUzique wrote:
i have the squarer ones. go for them jimmy they'll suit your chiselled jaw and suave looks.
you have approx. 3 hrs to go get some. good luck.
your future career depends upon it.
those look like glasses they wore in the 60s. Am I far off?
ray-ban wayfarer style originated in 1950's rock culture
the best corporate glasses are oliver peoples
the best corporate glasses are oliver peoples
libertarian benefit collector - anti-academic super-intellectual. http://mixlr.com/the-little-phrase/
True that.Uzique wrote:
ray-ban wayfarer style originated in 1950's rock culture
the best corporate glasses are oliver peoples
http://images.askmen.com/fashion/access … sses_1.jpg
There is a two inch diameter rod welded to a three inch diameter rod; both have the same length, and the three inch rod is also attached to a wall. A force of 267 kN is applied to the three inch rod in the direction of the wall, while an unspecified force P is applied in the opposite direction to the two inch rod. What is the compression stress on the three inch rod, and what force P will make the tensile stress on the two inch rod twice that?
Conceptually the problem is very easy (basically just apply stress=force/area, with the area easy to find), it's just that I've missed class and thus am not sure how much force is counted. Do I just use the 267 kN for the three inch rod, or double it to account for the opposite compression force from the wall, and does the tensile stress on the two inch rod derive only from P, or from P and the 267 kN in the opposite direction?
133.5 kn ->
_____________________ ________________________|
P <- [____two inch rod______]|________3 inch rod________|
133.5 kn -> |
Conceptually the problem is very easy (basically just apply stress=force/area, with the area easy to find), it's just that I've missed class and thus am not sure how much force is counted. Do I just use the 267 kN for the three inch rod, or double it to account for the opposite compression force from the wall, and does the tensile stress on the two inch rod derive only from P, or from P and the 267 kN in the opposite direction?
133.5 kn ->
_____________________ ________________________|
P <- [____two inch rod______]|________3 inch rod________|
133.5 kn -> |
Last edited by nukchebi0 (2010-09-15 18:01:47)
Section the rods in the appropriate places (between every force, and between the last force and the wall) to find internal force, use the internal force to find tenstion/compression in each section cut
if that doesn't make sense, you'll have to photocopy the picture and upload it, I can't really tell where the forces are acting on your diagram. Makes a difference where the forces are applied (middle/either end/etc)
if that doesn't make sense, you'll have to photocopy the picture and upload it, I can't really tell where the forces are acting on your diagram. Makes a difference where the forces are applied (middle/either end/etc)
I'll go paint. Give me five minutes to draw it
Edit:
Edit:
Last edited by nukchebi0 (2010-09-15 18:04:30)
Rod AB has cross sectional area pi
Rod BC has cross sectional area 2.25pi
Stress is force over cross sectional area.
P=60/2.25, or 24 kips
Rod BC has cross sectional area 2.25pi
Stress is force over cross sectional area.
P=60/2.25, or 24 kips
Two vectors A and B have precisely equal magnitudes. For the magnitude of A + B to be 62 times greater than the magnitude of A - B, what must be the angle between them?
wtf. that's just annoyingly confusing to set up.
put zero and state something clever about direction, and therefore angle, being irrelevant because they're only talking about magnitude.
put zero and state something clever about direction, and therefore angle, being irrelevant because they're only talking about magnitude.
Come on, that's easy. Set the first along the x-axis so there is no y component, with the x component the magnitude (m). The second is angled up some angle w, which is what you are trying to find. For the second vector, the x component is cos(w)m and the y component is sin(w)m.
Then, sqrt[(m+cos(w)m)2+(sin(w)m)2] = 62sqrt[(m-cos(w)m)2-(sin(w)m)2]. Solve for w from there.
Then, sqrt[(m+cos(w)m)2+(sin(w)m)2] = 62sqrt[(m-cos(w)m)2-(sin(w)m)2]. Solve for w from there.
Last edited by nukchebi0 (2010-09-26 17:55:13)
Oh yea I got it a long time ago haha
11. [1 point, 10 tries]
Two vectors A and B have precisely equal magnitudes. For the magnitude of A + B to be 62 times greater than the magnitude of A - B, what must be the angle between them?
Correct, computer gets: 1.85E+00 deg
I've always found simultaneous equations to be very straight forward, yet this one just makes my head hurt.
42x = 2y-1
94x = 3y+1
I know I have to convert it, but the problem is where to start. This may seem very basic to some of you, but I have no idea how to work this out. Help please?
42x = 2y-1
94x = 3y+1
I know I have to convert it, but the problem is where to start. This may seem very basic to some of you, but I have no idea how to work this out. Help please?
take logs to base 2 of equation 1 and logs to base 3 of equation 2henno13 wrote:
I've always found simultaneous equations to be very straight forward, yet this one just makes my head hurt.
42x = 2y-1
94x = 3y+1
I know I have to convert it, but the problem is where to start. This may seem very basic to some of you, but I have no idea how to work this out. Help please?
edit: 1 mo and i'll do it.
42x = 2y-1
94x = 3y+1
log242x = log22y-1
(2x)log24 = (y-1)log22
2x(2) = y-1)(1)
4x = y-1
x2 => 8x = 2y-2
log394x = log33y+1
(cba to type out this step)
4x(2) = y+1
==> 2y-2=y+1
y=3
==>8x-1 = 4x+1
x=0.5
Last edited by presidentsheep (2010-10-03 09:01:09)
I'd type my pc specs out all fancy again but teh mods would remove it. Again.