BF2S Forums need HELP on HOMEWORK PLZZZZ!!!!!!

easy : (lenght of a side x lenght of the imaginary line that is perpendicular to the segment and link to the center of the shape)/2 x number of sides

edit : this works for all the regular polygons. This pic will help you :

Last edited by -=raska=- (2007-02-07 17:22:41)

I typed in "geometry equations shapes area"  in google and found a load of sites.... here's one.

http://www.equationsheet.com/sheets/Equations-4/0.html

Will this help?

http://math.about.com/library/blmeasurement.htm
http://math2.org/math/geometry/areasvols.htm

I hate math, I got a test tomorrow. Goodluck

-=raska=- wrote:

easy : (lenght of a side x lenght of the imaginary line that is perpendicular to the segment and link to the center of the shape)/2 x number of sides

edit : this works for all the regular polygons. This pic will help you :

http://i128.photobucket.com/albums/p184 … r/area.png

yea, that sort of helps, I'm doing from pentagons to dodecagons, I'm still a little confused how that formula in the picture works, could you maybe explain it a little more please.

thareaper254 wrote:

-=raska=- wrote:

easy : (lenght of a side x lenght of the imaginary line that is perpendicular to the segment and link to the center of the shape)/2 x number of sides

edit : this works for all the regular polygons. This pic will help you :

http://i128.photobucket.com/albums/p184 … r/area.png

yea, that sort of helps, I'm doing from pentagons to dodecagons, I'm still a little confused how that formula in the picture works, could you maybe explain it a little more please.

ok just imagine that your regular polygon is a group of triangles... for example, lets say you want to find the surface area of a dodecagon. Then you divide the shape in 12 triangles as I did in my picture. Now you only have to find the surface area of one of the triangles, and because they are identical, multiply them by the number of triangles. The surface area formula of a triangle is (its base x its height)/2. On my pic, the base is one of the side and the height is the segment between the center of the shape to one of the side (perpendicularly).

so : (lenght of a side x lenght of the imaginary line that is perpendicular to the side and that links to the center of the shape)/2 x number of sides

-=raska=- wrote:

thareaper254 wrote:

-=raska=- wrote:

easy : (lenght of a side x lenght of the imaginary line that is perpendicular to the segment and link to the center of the shape)/2 x number of sides

edit : this works for all the regular polygons. This pic will help you :

http://i128.photobucket.com/albums/p184 … r/area.png

yea, that sort of helps, I'm doing from pentagons to dodecagons, I'm still a little confused how that formula in the picture works, could you maybe explain it a little more please.

ok just imagine that your regular polygon is a group of triangles... for example, lets say you want to find the surface area of a dodecagon. Then you divide the shape in 12 triangles as I did in my picture. Now you only have to find the surface area of one of the triangles, and because they are identical, multiply them by the number of triangles. The surface area formula of a triangle is (its base x its height)/2. On my pic, the base is one of the side and the height is the segment between the center of the shape to one of the side (perpendicularly).

so : (lenght of a side x lenght of the imaginary line that is perpendicular to the side and that links to the center of the shape)/2 x number of sides

thanks man, you helped me out alot, unlike these other douchebags that are spamming, thanks!

(apothem x perimeter) / 2
for any regular polygon

i know the first 100 decimal places of pi.  that might come in handy.  PM me if you need them.

tF-voodoochild wrote:

CoronadoSEAL wrote:

i know the first 100 decimal places of pi.  that might come in handy.  PM me if you need them.

you may know the first 100, but the internet and I know the first million digits of pi!

[Jealousy]

gene_pool wrote:

I am now scared of what is coming this year in maths

logically, math is the easiest subject.  they tell you the type of problems (with slight variation) and they tell you the solutions.  all you have to do is regurgitate. 

in other subjects the material is not as straight-forward.

tF-voodoochild wrote:

thareaper254 wrote:

thanks man, you helped me out alot, unlike these other douchebags that are spamming, thanks!

I see three spam posts... tops. Last time I try helping you with anything...

oo i know, I mean the people before that post that he made. I didn't mean the beginning posts.

If you don't know the length of the vertical of each triangle, use trig to work it out.