Announcement

Join us on Discord: https://discord.gg/nf43FxS
Ryan
Member
+1,230|5768|Alberta, Canada

Well, since I regarded that thread as being beneficial to myself, I think a new one should be created focussing only on the issue of answering other peoples homework questions or guiding them to a solution and not arguing over which uni/college is better, etc.

I usually go to Yahoo Answers to ask/find help to a question I'm stumped on, but I come here too to seek help and help other members with their homework problems.

modedit: College/University Homework Help Thread v1.0
Roc18
`
+655|4716|PROLLLY PROLLLY PROLLLY
Can someone help me find the expected annual cash flow to shareholders for this company F5 Technologies http://finance.yahoo.com/q?s=FFIV

I need it for a Discounted Cash Flow Valuation for a presentation I'm doing on the company to my school's board of trustees.
eusgen
Nugget
+402|5718|Jupiter
I get a Financial Accounting test in few weeks that I am going to need the whole bf2s's gang help with!
Jay
Bork! Bork! Bork!
+2,003|4283|London, England

Ryan wrote:

Well, since I regarded that thread as being beneficial to myself, I think a new one should be created focussing only on the issue of answering other peoples homework questions or guiding them to a solution and not arguing over which uni/college is better, etc.

I usually go to Yahoo Answers to ask/find help to a question I'm stumped on, but I come here too to seek help and help other members with their homework problems.
If you're having issues with calc, I suggest you look up videos by PatrickJMT on youtube. The guy breaks down difficult stuff and teaches you more in five minutes than I got from my professors lectures.
"Ah, you miserable creatures! You who think that you are so great! You who judge humanity to be so small! You who wish to reform everything! Why don't you reform yourselves? That task would be sufficient enough."
-Frederick Bastiat
Hurricane2k9
Pendulous Sweaty Balls
+1,538|4627|College Park, MD
need to write a dissertation on the heat death of the universe by tomorrow +1 for help
https://static.bf2s.com/files/user/36793/marylandsig.jpg
AussieReaper
( ͡° ͜ʖ ͡°)
+5,760|5078|what

Hurricane2k9 wrote:

need to write a dissertation on the heat death of the universe by tomorrow +1 for help
You should read The Last Question by Isaac Asimov.

Full text can be found here:

http://www.multivax.com/last_question.html


Please note, the above is complete fiction and should not be taken in anyway seriously or used for acadamia purposes. I mean, honestly - that ending? Child, please.
https://i.imgur.com/maVpUMN.png

"coz you a far cry from acclaim nigga ubisoft"
Pochsy
Artifice of Eternity
+702|4468|Toronto

Hurricane2k9 wrote:

need to write a dissertation on the heat death of the universe by tomorrow +1 for help
It's cute that you call it a dissertation.

PhD candidates write dissertations. You write essays.
The shape of an eye in front of the ocean, digging for stones and throwing them against its window pane. Take it down dreamer, take it down deep. - Other Families
Uzique
dasein.
+2,865|5396
lol i was just about to reply the same thing. a dissertation is a piece of work that clocks in normally at 15,000 words (for arts and humanities undergrads - scientists obviously have a lower word-limit). a PhD candidate can expect to write a piece of work from 30,000-50,000 words, typically (though there is no word limit for a PhD). my undergraduate thesis was 10,000 words and barely earned the 'dissertation' title. what can you possibly be writing overnight? it barely qualifies as an essay if it's < 2,500 words, imo. otherwise it's just a short assignment for a class. lol.
libertarian benefit collector - anti-academic super-intellectual. http://mixlr.com/the-little-phrase/
Hurricane2k9
Pendulous Sweaty Balls
+1,538|4627|College Park, MD
i'm a double PhD candidate
https://static.bf2s.com/files/user/36793/marylandsig.jpg
Uzique
dasein.
+2,865|5396
so it's a 500 word précis you're being asked to do then
libertarian benefit collector - anti-academic super-intellectual. http://mixlr.com/the-little-phrase/
Superior Mind
(not macbeth)
+1,755|5618
Do you think I would get away with creating an original porno as a visual anthropology project? We have seven minutes to present anything that relates to 'escapism.'


(srs)

Last edited by Superior Mind (2011-11-21 18:51:00)

AussieReaper
( ͡° ͜ʖ ͡°)
+5,760|5078|what

Superior Mind wrote:

Do you think I would get away with creating an original porno as a visual anthropology project? We have seven minutes to present anything that relates to 'escapism.'
Pretty sure that's already been done.

Search youtube for "I have the weirdest boner right now"
https://i.imgur.com/maVpUMN.png

"coz you a far cry from acclaim nigga ubisoft"
Superior Mind
(not macbeth)
+1,755|5618
It's been pulled down apparently.
Ryan
Member
+1,230|5768|Alberta, Canada

Jay wrote:

Ryan wrote:

Well, since I regarded that thread as being beneficial to myself, I think a new one should be created focussing only on the issue of answering other peoples homework questions or guiding them to a solution and not arguing over which uni/college is better, etc.

I usually go to Yahoo Answers to ask/find help to a question I'm stumped on, but I come here too to seek help and help other members with their homework problems.
If you're having issues with calc, I suggest you look up videos by PatrickJMT on youtube. The guy breaks down difficult stuff and teaches you more in five minutes than I got from my professors lectures.
Yea man I've watched his videos in the past, they are very helpful. Chemguy also has great videos for chemistry. I have a physics problem though. It seems so easy, but I'm stumped:

a projectile of mass 2.0kg approaches a stationary target body at 5.0m/s. The projectile is deflected through 60 degrees and its speed after the collision is 3m/s. What is the magnitude of the momentum of the target body after the collision?
Winston_Churchill
Bazinga!
+521|5664|Toronto | Canada

I've heard khan academy is good too.

@ryan - momentum will be conserved so you find momentum of projectile before, which will be equal to the sum of the projectiles momentum after and the target body's momentum after.  youll have to use the angle to calculate the momentum of them. 

try drawing it out, i always find that simplest
Ryan
Member
+1,230|5768|Alberta, Canada

Yea, wouldn't it be

(Mb)(vb)i + (Mt)(vt)i = (Mb)(vb)f + (Mt)(vt)f

Where Mb is the mass of the bullet, Mw mass of target, vb velocity of bullet, vt velocity of target

velocity of the target initial is 0, so I can cancel out (Mt)(vt)i
I'm solving for (Mt)(vt)f, which would be (Mb)(vb)i - (Mb)(vb)f

Lemme try something... lol

Agh, too hard trying to do it on a computer. I'll get it eventually.

Last edited by Ryan (2011-11-22 16:49:26)

unnamednewbie13
Moderator
+1,890|5697|USA

Learn excel and plug your formulas into it if you want to see them solved in real time.
Jay
Bork! Bork! Bork!
+2,003|4283|London, England

unnamednewbie13 wrote:

Learn excel and plug your formulas into it if you want to see them solved in real time.
Not very useful when he needs to know how to do it by hand for the test.
"Ah, you miserable creatures! You who think that you are so great! You who judge humanity to be so small! You who wish to reform everything! Why don't you reform yourselves? That task would be sufficient enough."
-Frederick Bastiat
unnamednewbie13
Moderator
+1,890|5697|USA

Jay wrote:

unnamednewbie13 wrote:

Learn excel and plug your formulas into it if you want to see them solved in real time.
Not very useful when he needs to know how to do it by hand for the test.
That's not the point. If you make an excel file to show it solved step-by-step, it becomes easier to double-check your work until you eventually don't need the file.

No use doing it all by hand if you take more of a chance of learning to do it the wrong way.
Ryan
Member
+1,230|5768|Alberta, Canada

I suck at excel. I figured it out with my noggin'
Stimey
­
+786|5045|Ontario | Canada

unnamednewbie13 wrote:

Jay wrote:

unnamednewbie13 wrote:

Learn excel and plug your formulas into it if you want to see them solved in real time.
Not very useful when he needs to know how to do it by hand for the test.
That's not the point. If you make an excel file to show it solved step-by-step, it becomes easier to double-check your work until you eventually don't need the file.

No use doing it all by hand if you take more of a chance of learning to do it the wrong way.
excel can solve math step by step?:
­
­
­
­
­
­
unnamednewbie13
Moderator
+1,890|5697|USA

Sure, as long as you tell it to.
Ryan
Member
+1,230|5768|Alberta, Canada

Lozana reported a 1.57% volume increase at 1 atm of pressue upon melting for lithium at 180.54 degrees C. If the density of the solid is 515kg/m^3, and the enthalpy of fusion is 3024J/mol, what will the melting point be at 1000atm?

Now, I searched this online a found the answer, but they didn't explain how to get it. They found delta V (change in volume) to be 2.12 x 10^-7 m^3/mol, then they said dT = delta T = 3.13K/mol or something weird like that and I don't get what it means. Help?

Do I just stick my delta v value into the C-C equation?
(HUN)Rudebwoy
Member
+45|5680
This is how they calculated:
Molar mass of lithium: M=6,941 g/mol
Density of solid lithium: 515 kg/m^3 = 515000 g/m^3 = 74196,8 mol/m^3 = 1,3477*10^-5 m^3/mol --> this is the volume of 1 mol lithium
1,57% volume change: (1,3477*10^-5)*1,0157 = 1,3689*10^-5 m^3
dV=(1,3689-1,3477)*10^-5 = 2,12*10^-7 m^3

Now, we have this equation here:

dT/dp = (Tm*dV)/dfH
Where dT is the change of the melting point in Kelvin, dp is the change of pressure in Pascal, Tm is the standard melting point, dV is the change of volume in m^3, and dfH is the enthalpy of fusion in Joule/mol.
So you have every data you need to find dT.
dp=1,01223*10^8 Pa
Tm=453,69 K
dV= 2,12*10^-7 m^3
dfH= 3024 Joule/mol

So dT=3,2195 K , which means that the new melting point (at 1000 atm) is 456,9 K
Ryan
Member
+1,230|5768|Alberta, Canada

Thanks. I managed to figure it out using the Clausius-Clapeyron eqn, which is a bit simpler for me, but now that you explain this, it makes sense.

Board footer

Privacy Policy - © 2021 Jeff Minard