Alright I'm writing line diagrams for different compounds, but I want to make sure i'm doing it correctly. So, how would you draw a line diagram for NO3 -1? The question I have in specific is about the valence electrons. Would that compound have 5+7(3)=26, or would it be 5+6(3)+1=24? That -1 is throwing me off. Thanks.
it would be
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:0:
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N:
/ \
:0: :0:
`` ``
???
so it would be 5+6(3)+1=24
i think im wrong
sorry... i just took chem 1 like 3 months ago too lol
..
:0:
.. | ..
0=N-0:
`` ` ``
?????????
ok i give up i am no help sorry
..
:0:
|
N:
/ \
:0: :0:
`` ``
???
so it would be 5+6(3)+1=24
i think im wrong
sorry... i just took chem 1 like 3 months ago too lol
..
:0:
.. | ..
0=N-0:
`` ` ``
?????????
ok i give up i am no help sorry
Last edited by =NHB=Shadow (2010-02-23 17:30:53)
.. ..
: O = N - O:
| ``
: O :
``
5 + 6(3) + 1 = 24 Total Electrons
: O = N - O:
| ``
: O :
``
5 + 6(3) + 1 = 24 Total Electrons
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:0:
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N
// \
:0: :0:
`` ``
Correct configuration, although the double bonds can exist between any nitrogen and oxygen making it a resonance structure.
5 + 6(3) + 1 = 24 valence
:0:
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N
// \
:0: :0:
`` ``
Correct configuration, although the double bonds can exist between any nitrogen and oxygen making it a resonance structure.
5 + 6(3) + 1 = 24 valence
Last edited by Reddhedd (2010-02-23 22:20:59)
:0: :0:
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o
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:0:0:0:
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o
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