Does anyone know what the bottom problem's notation means?
"people in ny have a general idea of how to drive. one of the pedals goes forward the other one prevents you from dying"
Fuck I'm so glad I never have to do math ever again.
i'm pretty sure sequences and series is about doing trial and error.
i can't exactly do that when i don't know what the problem is askingmafia996630 wrote:
i'm pretty sure sequences and series is about doing trial and error.
"people in ny have a general idea of how to drive. one of the pedals goes forward the other one prevents you from dying"
I never managed to understand sequences and series, we had so little time to get it, most of the time in that math course was spent on integration :S.
I passed the course with an 8 (out of 10) though, woot.
I passed the course with an 8 (out of 10) though, woot.
helpfulSydney wrote:
I never managed to understand sequences and series, we had so little time to get it, most of the time in that math course was spent on integration :S.
I passed the course with an 8 (out of 10) though, woot.
"people in ny have a general idea of how to drive. one of the pedals goes forward the other one prevents you from dying"
I kno, rite.
Isn't that how all math is solved?mafia996630 wrote:
i'm pretty sure sequences and series is about doing trial and error.
It could mean find M such that the absolute value of (n+2)/n - 1 is less than e for all n bigger than M, ie find M such that
-e< (n+2)/n - 1 < e for all n>M.
If that is right i think you need M=2/e
-e< (n+2)/n - 1 < e for all n>M.
If that is right i think you need M=2/e
yeah i think it has something to do with error, shittiest section ever, don't do ita_member wrote:
It could mean find M such that the absolute value of (n+2)/n - 1 is less than e for all n bigger than M, ie find M such that
-e< (n+2)/n - 1 < e for all n>M.
If that is right i think you need M=2/e