God, it's been 3 hours since you posted.Sheen1101 wrote:
nobody is going to help me
Just leave the coefficients of the first answer as fractions.. especially with 6/7 and 13/3. If you make them decimals then they aren't exact.
Just leave the coefficients of the first answer as fractions.. especially with 6/7 and 13/3. If you make them decimals then they aren't exact.
f(x) = 6x6 - 2x4 + 13x2
6/7x7 + 2/5x5 + 13/3x3 + C
Your book is wrong if it has another answer. (Derivate it and you see)
f(x) = 5(√x) + 4cos(x)
5x½ + 4cos(x)
....
And I get the same as you here aswell, what are the correct answers?
6/7x7 + 2/5x5 + 13/3x3 + C
Your book is wrong if it has another answer. (Derivate it and you see)
f(x) = 5(√x) + 4cos(x)
5x½ + 4cos(x)
....
And I get the same as you here aswell, what are the correct answers?
You did nothing...Gawwad wrote:
(x) = 5(√x) + 4cos(x)
5x½ + 4cos(x)
f(x) = 5x1/2 + 4cosx
I = ∫f(x)dx
= ∫ [5x1/2 + 4cosx] dx
= 5*x3/2/(3/2) + 4sinx + C
I = 10/3*x3/2 + 4sinx + C
Does anybody know how to do this problem:
I can't seem to get the answer......
I can't seem to get the answer......
I get 162π/5...Sheen1101 wrote:
Does anybody know how to do this problem:
http://img2.imageshack.us/img2/2531/19659454.jpg
I can't seem to get the answer......
Also, with the ones that you have previously gotten "wrong"... is there somewhere in this webassign interface that explains the input of the answers. Last year with my maths course, the online tests required the answers to be input in the same way we input things into the Maple maths program. Just a thought...
thanks! and to your other post, webassign does not really tell me how to enter the answers unless mentioned in the problem like enter as in fraction or to how many decimal places. The ones that say were wrong I eventually got them right when I went to a math tutor.....webassign wanted the answer in fraction not decimals so that's why I got them wrong in the first place....mcminty wrote:
I get 162π/5...Sheen1101 wrote:
Does anybody know how to do this problem:
http://img2.imageshack.us/img2/2531/19659454.jpg
I can't seem to get the answer......
notice the "..."mcminty wrote:
You did nothing...Gawwad wrote:
(x) = 5(√x) + 4cos(x)
5x½ + 4cos(x)
f(x) = 5x1/2 + 4cosx
I = ∫f(x)dx
= ∫ [5x1/2 + 4cosx] dx
= 5*x3/2/(3/2) + 4sinx + C
I = 10/3*x3/2 + 4sinx + C
I cba type the whole shit as I got the same answer.