Except that within quantum mathmatics, .99999... (repeating) is not a real number, simply a decimal approximation for a fraction. In functional mathmatics, your proof is indeed true. However, in applied mathmatics (as in science), it is false.i3igpete wrote:
suppose x = .999....
then 10x = 9.999....
10x - x = 9x = 9.999... - .999... = 9
9x = 9
x = 1 = .999...
therefore, .999... = 1
oh god.....
what have i started
what have i started
mine's better...
I just happen to stumble on this thread. . . . .
and its safe to say there are guys here (in this thread in particular) definitely not getting laid if they are arguing over mathmatics on a video game website. . . . .
and its safe to say there are guys here (in this thread in particular) definitely not getting laid if they are arguing over mathmatics on a video game website. . . . .
You are.liquidat0r wrote:
Am I right or what?liquidat0r wrote:
Each guy pays $9.
The total in the till is now $27.
The receptionist takes $2.
That leaves $25 in the till, 1 with each man, (making 3) and 2 with the receptionist. That's 25 + 1 + 1 + 1 + 2 = 30.The receptionist has the last two dollars.Andoura wrote:
Wheres the last dollar?
---
*wonders if he just made a very obvious mistake*
.
But that problem was solved long ago. If you read it you would find the new problem is whether or not 0.9=1
Last edited by petermassingale (2007-06-28 18:38:17)
25+3=28 then he pocketed the 2 dollarsAndoura wrote:
Here the proof math are false:
3 guys goes to an hotel, it will cost 30$ for one night. So they each pay 10$ which makes 30$. Few hours later the receptionist realized it was 25$ for the night, so he have to give them back 5$. But 5$ in 3 is hard, so he decide to give them back 1$ each and keep 2$ for him. So each guy payed 9$ what makes a total of 27$. Add to those 27$ you add the 2$ of the receptionist which makes 29$...
Wheres the last dollar?
theirs no illusion, fake statement or stuff like that!
The problem got solved in the first reply. Now why is this thread still alive?
well if .9999~ = 1 then any recurring decimal must round up , if it didnt .9999~ wouldnt = 1???Smithereener wrote:
Someone does care - me. And I know, there was a thread about the problem a few months ago. Went on for like 12+ pages till it got closed. But my post wasn't about the .99999~=1 problem. I just wanted to know this guy's reasoning for .3333~ being rounded to .34.Yaocelotl wrote:
No one cares anymore, the "problem" was solved long ago, go to sleep.Smithereener wrote:
Hold up. How is .333~ rounded to .34? That makes no sense.
if .9999~ = 1 then .3333~ cant = .3333~ therefore .3333~ X 3 cant be .9999~ or 1 so .999~ cant be 1????
btw im 13 so i dont really know alot im not saying .9999~ doesnt = 1 im questioning
btw im 13 so i dont really know alot im not saying .9999~ doesnt = 1 im questioning
0.3333~ can't be rounded to 0.34 it's rounded to 0.3...
EDIT: And stop posting already...
http://en.wikipedia.org/wiki/0.99999I0973 wrote:
if .9999~ = 1 then .3333~ cant = .3333~ therefore .3333~ X 3 cant be .9999~ or 1 so .999~ cant be 1????
btw im 13 so i dont really know alot im not saying .9999~ doesnt = 1 im questioning
EDIT: And stop posting already...
Last edited by Gawwad (2007-06-28 12:20:48)
im not talking about it being rounded im talking about what .3333~ is equal to. if .999~ = 1 then .3333~ cant = .3333~ and so .3333~ (1/3) X 3 cant = 1???
0.3333~ ofcourse equals to 0.3333~ as it has to equal with it self. I don't really follow you here?I0973 wrote:
im not talking about it being rounded im talking about what .3333~ is equal to. if .999~ = 1 then .3333~ cant = .3333~ and so .3333~ (1/3) X 3 cant = 1???
0.9999~ = 3/3
0.3333~ = 1/3
(I must really be bored to still reply to this thread )
I think your grammar problems are more important than any you 'find' with mathematics.Andoura wrote:
Here the proof math are false:
3 guys goes to an hotel, it will cost 30$ for one night. So they each pay 10$ which makes 30$. Few hours later the receptionist realized it was 25$ for the night, so he have to give them back 5$. But 5$ in 3 is hard, so he decide to give them back 1$ each and keep 2$ for him. So each guy payed 9$ what makes a total of 27$. Add to those 27$ you add the 2$ of the receptionist which makes 29$...
Wheres the last dollar?
theirs no illusion, fake statement or stuff like that!
He takes 5$ from them so the guys spent 25$ he gives them 3$ back which is 28$ and the hotel has 2$ which equals 30$. I think you added something wrong somewhere. Its correct if you do it right i think someone who can't properly add shouldn't try to prove math wrong.
You Owned Yourself
You Owned Yourself
Last edited by †[AøT]§tèálth† (2007-06-28 14:53:48)
i dont know man...apparently some chicks are into guys who talk nerdyfadedsteve wrote:
I just happen to stumble on this thread. . . . .
and its safe to say there are guys here (in this thread in particular) definitely not getting laid if they are arguing over mathmatics on a video game website. . . . .
when we party at my house my roommate and i will be drunk talking about chemistry/biology and people think its hilarious.
worst part is we actually make sense
They paid $27 because the receptionist stole the two dollars. You subtract two dollars from $27 instead of adding it.
That's the simplest way of putting it. It's a mistake of adding and subtracting.
That's the simplest way of putting it. It's a mistake of adding and subtracting.
Last edited by Drakef (2007-06-29 14:10:55)
Be fair, English isn't his native languageunnamednewbie13 wrote:
I think your grammar problems are more important than any you 'find' with mathematics.Andoura wrote:
Here the proof math are false:
3 guys goes to an hotel, it will cost 30$ for one night. So they each pay 10$ which makes 30$. Few hours later the receptionist realized it was 25$ for the night, so he have to give them back 5$. But 5$ in 3 is hard, so he decide to give them back 1$ each and keep 2$ for him. So each guy payed 9$ what makes a total of 27$. Add to those 27$ you add the 2$ of the receptionist which makes 29$...
Wheres the last dollar?
theirs no illusion, fake statement or stuff like that!
bloody french
Edit:at least I assume he's french. If he isn't then he fails at grammar.
Last edited by petermassingale (2007-06-28 18:51:37)
Which gives you $23...............Drakef wrote:
You subtract two dollars from $25 instead of adding it.
The travellers in total PAID $27, that means they don't have the $27. You have to add the returned $3 to the $27 to account for all the money.Andoura wrote:
Here the proof math are false:
3 guys goes to an hotel, it will cost 30$ for one night. So they each pay 10$ which makes 30$. Few hours later the receptionist realized it was 25$ for the night, so he have to give them back 5$. But 5$ in 3 is hard, so he decide to give them back 1$ each and keep 2$ for him. So each guy payed 9$ what makes a total of 27$. Add to those 27$ you add the 2$ of the receptionist which makes 29$...
Wheres the last dollar?
theirs no illusion, fake statement or stuff like that!
Why............just, someone tell me..........why?
Why not?Bubbalo wrote:
Why............just, someone tell me..........why?
Because it's stupid. There's only one person who doesn't get it, and that's the thread starter, and he probably never will.
well what im saying...Gawwad wrote:
0.3333~ ofcourse equals to 0.3333~ as it has to equal with it self. I don't really follow you here?I0973 wrote:
im not talking about it being rounded im talking about what .3333~ is equal to. if .999~ = 1 then .3333~ cant = .3333~ and so .3333~ (1/3) X 3 cant = 1???
0.9999~ = 3/3
0.3333~ = 1/3
(I must really be bored to still reply to this thread )
you say .33333~ has to equal itself ( .3333~) and nothing else, but .99999~ doesnt equal itself then surely any other recuring decimal must also not be equal to itself but something of a higher value ?
.33333~ = .3333~ ?
but...
.9999~ doesnt = .99999~
doesnt the rule aply to all recurring numbers??
just do your 436 dude...
You guys dont get it, Its not about 25+3+2=30 , neither 27-2=25
Its about the logic of the way andoura put it that doesnt give you the right answer.
Hes tryin to calculate the total amount of money in this problem with a logical math thinking by saying that everyone paid 9$ with the 1 $ being returned to them : 9x3= 27 and 2 $ kept by receptionist 27+2=29.
of course there is no missing dollar,,, but how he calculated it is not wrong but still gives a wrong answer..
Its about the logic of the way andoura put it that doesnt give you the right answer.
Hes tryin to calculate the total amount of money in this problem with a logical math thinking by saying that everyone paid 9$ with the 1 $ being returned to them : 9x3= 27 and 2 $ kept by receptionist 27+2=29.
of course there is no missing dollar,,, but how he calculated it is not wrong but still gives a wrong answer..