BF3S Forums Need Help With Physics =(

CDK3Y
Member
Offline No Xfire No stats No stats No Email No PM No website
+25|2674|BEHIND YOU!
Two rugby players are running towards each other. They are 37 m apart. If one is accelerating from rest at 0.5 m/s^2 and the other was already moving at 3.1 m/s and maintains her speed,
a) how long before they crunch together?
b) how fast was the accelerating player going?
c) how far each player ran?




DONT get the damn question....any help would be appreciated.....Motion and Forces sucks big time sad
blademaster
I'm moving to Brazil
Offline No Xfire No stats No stats No stats No Email No PM No website
+2,075|3180
you ll find ur answer there
http://www.physicsforums.com/archive/in … 07482.html

Last edited by blademaster (2008-01-12 02:13:19)

Vub
The Power of Two
Offline No Xfire No stats No stats No stats No Email No PM No website
+188|3029|Sydney, Australia
a) OK, let the distance travelled by person A in t seconds be 1/2 * 0.5m/s/s * t^2 (formula). Distance travelled by person B is 3.1*t. Adding them gives you a quadratic equation: t^2 + 12.4*t - 148 = 0. Solving this, you get t = 7.45 seconds.

b) Using the equation v = u + a*t where v is final velocity, u is initial velocity, a is acceleration and t is time, you get: v = 0 + 0.5 * 7.45; v = 3.73m/s

c) Person A: using equation distance = u*t + 1/2*a*t^2 you get distance = 13.88m.
    Person B: distance = speed * time: distance = 23.1m

Last edited by Vub (2008-01-12 07:55:29)

Nappy
Apprentice
Offline No stats No Email No PM
+151|2764|NSW, Australia

BF2S Honors:
Donator

theyre chicks!

sweeet
Entertayner
Member
Offline No stats No stats No Email No PM
+826|3105

BF2S Honors:
BF2S Game Admin
Donator

Lolz... Fizix.
Tehremos
Parcel of ol' Crams
Offline No stats No stats No Email No PM No website
+128|2942|Somersetshire

Nappy wrote:

theyre chicks!

sweeet
lol thats what i was thinking lol

Board footer

Privacy Policy - © 2014 Jeff Minard